Pass in Type as Parameters

[k3zi]

I ran across an issue where Swift wasn't allowing me to supply a type that was produced from a function

func classTypeForTable(tableView: UITableView) -> ReusableCell.Type {
     return MyCell.Type
}

// In cellForRow //
let cellClass = classTypeForTable(tableView)
let cell = tableView.dequeueReusableCell(indexPath) as cellClass

^^^^^^ This last line fails because "cellClass is not a type"

I was able to get around this by changing the dequeue function and adding another:

func dequeueReusableCell<T: UITableViewCell where T: Reusable>(indexPath indexPath: NSIndexPath) -> T {
        return self.dequeueReusableCell(indexPath, cellType: T.self)
    }

func dequeueReusableCell<T: UITableViewCell where T: Reusable>(indexPath: NSIndexPath, cellType: T.Type) -> T {
       return self.dequeueReusableCellWithIdentifier(T.reuseIdentifier, forIndexPath: indexPath) as! T
    }

This would seem like a function you might want to add for advanced users...

[AliSoftware]

Could be a great addition in case you have the type in a variable indeed 👍

BTW, wouldn't it be even simpler to implement it using a default value for this additional parameter?

func dequeueReusableCell<T: UITableViewCell where T: Reusable>(indexPath: NSIndexPath, cellType: T.Type = T.self) -> T {
  return self.dequeueReusableCellWithIdentifier(T.reuseIdentifier, forIndexPath: indexPath) as! T
}

This way we'd get both implementations for free in less code 😉

---

Don't hesitate to make a Pull Request to add this feature.

I definitely need to implement #7 soon so people can contribute with the assurance they won't break anything, but in the meantime if you use the Sample project to demonstrate that alternate use case, so it could at least confirm things can continue to work both with the current syntax and with your new API using the additional parameter.

[k3zi]

Like the merged function! Didn't realize I could put them together...

I'll go ahead and create a PR when I can.

[k3zi]

It was also necessary for me to replace T.reuseIdentifier with cellType.reuseIdentifier because T is a reference to the superclass of cellType (in the above example: ReusableCell).