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指针是肯定必须成为AST的一部分的,起码后端得知道啥是指针。然后才能调用各种C语言函数。
我并不认为这个东西是必须暴露的(我其实更希望它被包起来),但是它不可避免啊(puts要的可不是i8的数组)。
The text was updated successfully, but these errors were encountered:
我现在才意识到想要make 字符串 鬼特 again是多么困难的事情
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emmmm调用C函数的话,不用暴露指针给程序吧- -底层就好啦
起码这个隐式转换肯定是要编译器完成的
@SmallLuma
Seng-Jik
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指针是肯定必须成为AST的一部分的,起码后端得知道啥是指针。然后才能调用各种C语言函数。
我并不认为这个东西是必须暴露的(我其实更希望它被包起来),但是它不可避免啊(puts要的可不是i8的数组)。
The text was updated successfully, but these errors were encountered: