038-pandigital-multiples.ipynb

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    "# Pandigital multiples\n",
    "## Problem 38 \n",
    "\n",
    "<div class=\"problem_content\" role=\"problem\">\n",
    "<p>Take the number 192 and multiply it by each of 1, 2, and 3:</p>\n",
    "<blockquote>192 &#215; 1 = 192<br/>\n",
    "192 &#215; 2 = 384<br/>\n",
    "192 &#215; 3 = 576</blockquote>\n",
    "<p>By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)</p>\n",
    "<p>The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).</p>\n",
    "<p>What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , <var>n</var>) where <var>n</var> &gt; 1?</p>\n",
    "</div>"
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   "source": [
    "def solve():\n",
    "    # Your code here\n",
    "    \n"
   ]
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   "source": [
    "## Solution"
   ]
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   "source": [
    "solve()"
   ]
  }
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