Calls given function after specified amount of milliseconds.
Several thing about it's work:
- does not re-render component;
- automatically cancel timeout on cancel;
- automatically reset timeout on delay change;
- reset function call will cancel previous timeout;
- timeout will NOT be reset on function change. It will be called within the timeout, you have to reset it on your own when needed.
import * as React from 'react';
import { useTimeoutFn } from 'react-use';
const Demo = () => {
const [state, setState] = React.useState('Not called yet');
function fn() {
setState(`called at ${Date.now()}`);
}
const [isReady, cancel, reset] = useTimeoutFn(fn, 5000);
const cancelButtonClick = useCallback(() => {
if (isReady() === false) {
cancel();
setState(`cancelled`);
} else {
reset();
setState('Not called yet');
}
}, []);
const readyState = isReady();
return (
<div>
<div>{readyState !== null ? 'Function will be called in 5 seconds' : 'Timer cancelled'}</div>
<button onClick={cancelButtonClick}> {readyState === false ? 'cancel' : 'restart'} timeout</button>
<br />
<div>Function state: {readyState === false ? 'Pending' : readyState ? 'Called' : 'Cancelled'}</div>
<div>{state}</div>
</div>
);
};
const [
isReady: () => boolean | null,
cancel: () => void,
reset: () => void,
] = useTimeoutFn(fn: Function, ms: number = 0);
fn
: Function
- function that will be called;ms
: number
- delay in milliseconds;isReady
: ()=>boolean|null
- function returning current timeout state:false
- pendingtrue
- callednull
- cancelled
cancel
: ()=>void
- cancel the timeoutreset
: ()=>void
- reset the timeout