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In an image, after subtracted by dark, divided by flat, sky still left.
I think up a good way to eliminate the sky.
Assume the distribution of gas in sky is equivalent everywhere.
So there is a simple relation between sky intensity and elevation.
I = I_{0}sec\theta + A,
where I is the intensity of the sky you observe,
I_{0} is the intensity of the sky in \theta = 0 degree,
A is real const
The text was updated successfully, but these errors were encountered:
How to calibrate the sky intensity?
In an image, after subtracted by dark, divided by flat, sky still left.
I think up a good way to eliminate the sky.
Assume the distribution of gas in sky is equivalent everywhere.
So there is a simple relation between sky intensity and elevation.
I = I_{0}sec\theta + A,
where I is the intensity of the sky you observe,
I_{0} is the intensity of the sky in \theta = 0 degree,
A is real const
The text was updated successfully, but these errors were encountered: