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English Version

题目描述

字符串轮转。给定两个字符串s1s2,请编写代码检查s2是否为s1旋转而成(比如,waterbottleerbottlewat旋转后的字符串)。

示例1:

 输入:s1 = "waterbottle", s2 = "erbottlewat"
 输出:True

示例2:

 输入:s1 = "aa", "aba"
 输出:False

提示:

  1. 字符串长度在[0, 100000]范围内。

说明:

  1. 你能只调用一次检查子串的方法吗?

解法

Python3

class Solution:
    def isFlipedString(self, s1: str, s2: str) -> bool:
        return len(s1) == len(s2) and s1 in (s2 * 2)

Java

class Solution {
    public boolean isFlipedString(String s1, String s2) {
        return s1.length() == s2.length() && (s2 + s2).indexOf(s1) != -1;
    }
}

Go

func isFlipedString(s1 string, s2 string) bool {
	return len(s1) == len(s2) && strings.Contains(s1+s1, s2)
}

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